Submission #1873349

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Source Code Expand

#include<iostream>
#include<string>
using namespace std;
typedef long long int ll;

int main() {
	string s;
	cin >> s;
	int n = s.length();
	ll ans = 0;
	for(int i = 0; i < 1 << (n - 1); i++){
		ll sum = 0;
		ll num = s[0] - '0';
		for(int j = 0; j < n - 1; j++){
			if(i & (1 << j)){
				num *= 10;
				num += s[j + 1] - '0';
			}else{
				sum += num;
				num = s[j + 1] - '0';
			}
		}
		sum += num;
		ans += sum;
	}
	cout << ans << endl;
	return 0;
}

Submission Info

Judge Result